A conductivity cell has a cell constant of 0.5 cm − 1 . This cell when filled with 0.01 M NaCl solution has a resistance of 384 ohms at 2 5 ∘ C . Calculate the equivalent conductance of the given solu

Question

A conductivity cell has a cell constant of 0.5 cm − 1 . This cell when filled with 0.01 M NaCl solution has a resistance of 384 ohms at 2 5 ∘ C . Calculate the equivalent conductance of the given solution.

TestHub · Accepted Answer

​ Equivalent conductance, Λ e q ​ = Normality κ × 1000 ​ where, κ (Specific conductance) = C × a l ​ = R 1 ​ × a l ​ = 384 1 ​ × 0.5 = 1.302 × 1 0 − 3 ohm − 1 cm − 1 ∴ Λ e q ​ = 0.01 1.302 × 1 0 − 3 × 1000 ​ = 130.2 ohm − 1 cm 2 ( g eq ) − 1 ​

Chemistry - Electrochemistry Question with Solution | TestHub

Options:

Doubts & Discussion