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ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsMedium2 minPYQ_2014

ChemistryMediumsingle choice

When $0.1 m o l {M n O}_{4}^{2 -}$ is oxidized the quantity of electricity required to completely $M n O_{4}^{2 -}$ to $M n O_{4}^{-}$ isNEET 2014

Answer:

Solution:

$M n O_{4}^{2 -} \to M n O_{4}^{-}$
$0.1$ mole
$v . f . = 1$
So, $0.1 m o l e = 96500 \times 0.1$
$= 9650 C$ charge is required

Stream:NEETSubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells

⏱ 2mℹ️ Source: PYQ_2014

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