Chemistry - Electrochemistry Question with Solution | TestHub

Given : $E_{{\mathrm{H}}^{+}/{\mathrm{H}}_2}=18\times 10^{-3}\mathrm{V},\left[{\mathrm{H}}^{+}\right]=?$ Applying Nernst equation, $E_{{\mathrm{H}}^{+}/{\mathrm{H}}_2}=E_{{\mathrm{H}}^{+}/{\mathrm{H}}_2}^{\circ }-\frac{0.0591}{1}\log \frac{1}{\left[{\mathrm{H}}^{+}\right]}$ $18\times 10^{-3}\mathrm{V}=0+0.0591\log \left[{\mathrm{H}}^{+}\right]$ $18\times 10^{-3}\mathrm{V}=0.0591\log \left[{\mathrm{H}}^{+}\right]$ $\log \left[{\mathrm{H}}^{+}\right]=0.3046$ $\therefore \left[{\mathrm{H}}^{+}\right]=\mathrm{antilog}(0.3046)=2.02=2.0$