For Zn 2 + ∣ Zn , E ∘ = − 0.76 V then EMF of the cell Zn / Zn 2 + ( 1 M ) ∣ 2 H + ( 1 M ) ∣ H 2 (1 atm) will be

cell ∘ = right ∘ − left ∘ ∵ cell = 0 − ( 0 − 0.76 ) = 0.76 V

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ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsMedium2 minPYQ_2012

ChemistryMediumsingle choice

For $Zn^{2 +} ∣ Zn, E^{\circ} = - 0.76 V$ then EMF of the cell $Zn / Zn^{2 +} (1 M) ∣ 2 H^{+} (1 M) ∣ H_{2}$ (1 atm) will be

Answer:

Solution:

$cell \circ = \frac{\circ}{right} - \frac{\circ}{left}$ $∵$ cell $= 0 - (0 - 0.76) = 0.76 V$

Stream:AIIMSSubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells

⏱ 2mℹ️ Source: PYQ_2012

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