The theoretical efficiency of a hypothetical cell is 84% . The cell reaction is - A ( s ) + B 2 + ( a q . ) → A 2 + ( a q . ) + B ( s ) ; Δ H = − 285 kj The standard EMF of cell ( in volts) is.

Relation Δ G = − n FE Given n = 2 and Δ G = 285000 J , we can calculate E : E = 2 × 96500 285000 E ≈ 1.24 V

Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryRelationship between Eº, DGº & KeqMedium2 minQB

ChemistryMediumnumerical

The theoretical efficiency of a hypothetical cell is $84%$ . The cell reaction is -

$A (s) + B^{2 +} (a q .) \to A^{2 +} (a q .) + B (s); Δ H = - 285 kj$

The standard EMF of cell ( in volts) is.

Answer:

1.24

Solution:

Relation

$Δ G = - n FE$

Given $n = 2$ and $Δ G = 285000 J$ , we can calculate $E$ :

$E = \frac{285000}{2 \times 96500}$

$E \approx 1.24 V$

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Relationship between Eº, DGº & Keq

⏱ 2mℹ️ Source: QB

Loading discussions...