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ChemistryElectrochemistryMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

0.02 equivalent of Ag was deposited in an electrolysis experiment. If same quantity of a electricity is passed through a gold solution, 1.314 g of gold is deposited. Find oxidation state of the gold. (Atomic mass of Au = 197)

Answer:

3.00

Solution:

$A g^{+} + e^{-} \to \underset{1 mol (1 e q .)}{Ag}$

0.02 q. of Ag = 0.02 F = 0.02 $\times$ 96500 = 1930 C

1.314 Au is deposited by 0.02 F

197 is deposited by $\frac{0.02}{1.314} \times 197 = 3 F$

Stream:NTA_ABHYASSubject:ChemistryTopic:ElectrochemistrySubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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