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Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryConductance/conductivity/^mHard2 minPYQ_2009

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The equivalent conductance of $\frac{M}{32}$ solution of a weak monobasic acid is 8.0 mho $cm^{2}$ and at infinite dilution is 400 mho $cm^{2}$ , The dissociation constant of this acid is -NEET 2009 (Mains)

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Answer:

Solution:

$α = K_{a} \frac{A _{C}}{A _{\infty}} = \frac{8}{400} = C^{2} = \frac{1}{32} \times \frac{8}{400} \times \frac{8}{400} = 1.25 \times 1 0^{- 5}$

Stream:NEETSubject:ChemistryTopic:ElectrochemistrySubtopic:Conductance/conductivity/^m

⏱ 2mℹ️ Source: PYQ_2009

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