Chemistry - Electrochemistry Question with Solution | TestHub

$2{\mathrm{AgCl}}_{(s)}+{\mathrm{H}}_{2(g)}\to 2{\mathrm{HCl}}_{(aq)}+2{\mathrm{Ag}}_{(s)}$ The activities of solids and liquids are taken as unity and at low concentrations, the activity of a solute is approximated to its molarity. The cell reaction will be $${\mathrm{Pt}}_{(s)}\mid {\mathrm{H}}_{2(\mathrm{g})},1\text{ bar }\left|{\mathrm{H}}_{(aq)}^{+}1\mathrm{M}\Vert {\mathrm{AgCl}}_{(aq)}1\mathrm{M}\right|{\mathrm{Ag}}_{(s)}$$