Chemistry - Coordination Chemistry Question with Solution | TestHub
Consider the following ligands en, bn, tn, pn, , ox , bipy
If total number of bidentate ligands = x
If total number of ligands which contains chiral centre = y
If total number of monodentate ligands = z
then find the value of
Answer:
Solution:
Let's analyze each ligand:
en (ethylenediamine): bidentate, no chiral center.
bn (1,2-diaminopropane): bidentate, contains one chiral center.
tn (1,3-diaminopropane): bidentate, no chiral center.
pn (propylenediamine): Same as bn, bidentate, contains one chiral center.
dmg⁻¹ (dimethylglyoximato): bidentate, no chiral center.
ox⁻² (oxalate): bidentate, no chiral center.
acac⁻¹ (acetylacetonato): bidentate, no chiral center.
OAc⁻¹ (acetate): monodentate, no chiral center.
NO₂⁻ (nitrite): monodentate, no chiral center.
NH⁻² (imide): monodentate, no chiral center.
bipy (2,2'-bipyridine): bidentate, no chiral center.
Total bidentate ligands (x): en, bn, tn, pn, dmg⁻¹, ox⁻², acac⁻¹, bipy = 8
Total ligands with chiral center (y): bn, pn = 2
Total monodentate ligands (z): OAc⁻¹, NO₂⁻, NH⁻² = 3
Calculate :
