Both [ Ni ( CO ) 4 ] and [ Ni ( CN ) 4 ] 2 − are diamagnetic. The hybridisations of nickel in these complexes, respectively, are

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Both [ Ni ( CO ) 4 ​ ] and [ Ni ( CN ) 4 ​ ] 2 − are diamagnetic. The hybridisations of nickel in these complexes, respectively, are

TestHub · Accepted Answer

The oxidation state of Ni in [ N i ( CO ) 4 ​ ] is 0. CO is a strong field ligand, but since Ni is in a zero oxidation state, its 3d⁸4s² configuration leads to sp³ hybridization and a tetrahedral geometry. In [ N i ( CN ) 4 ​ ] 2 − , Ni is in the +2 oxidation state (3d⁸). CN⁻ is a strong field ligand, causing pairing of electrons, leading to dsp² hybridization and a square planar geometry.

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