Chemistry - Salt Analysis Question with Solution | TestHub

Na₂SO₄ + C $\stackrel{\Delta }{\to }$ Na₂S

So, $A=N{a}_{2}S$.

$N{a}_{2}S$ reacts with sodium nitroprusside, $N{a}_2[Fe(CN{)}_{5}NO]$, to form a purple complex, $B$.

In the complex ion $[Fe(CN{)}_{5}NO{]}^{4-}$, the oxidation state of Fe is $0$.

Thus, Fe has a configuration of $3d^{6}4s^2$, i.e., a total of 8 d-electrons.

Since $C{N}^{-}$ is a strong field ligand, the complex is low spin:

$t_{2g}^6{e}_g^0$

Hence,

$x=6$ ,$y=0$.

$x^2-y^2=6^2-0^2=36$.