In the complex of type [M(AA)(BC)de], number of pairs of enantiomers are ' $w$ '.
The complex 'bis(ethylenediamine)dinitrocobalt (III) bromide' shows 'x' linkage isomers, 'y' geometrical isomers and 'z' optically active isomers.
Report for : [yw – xz]

Question

In the complex of type [M(AA)(BC)de], number of pairs of enantiomers are ' $w$ '.

The complex 'bis(ethylenediamine)dinitrocobalt (III) bromide' shows 'x' linkage isomers, 'y' geometrical isomers and 'z' optically active isomers.

Report for : [yw – xz]

TestHub · Accepted Answer

Final Answer:

w = 5 (pairs of enantiomers for [M(AA)(BC)de])

x = 3 (linkage isomers for [Co(en)₂(NO₂)₂]Br)

y = 2 (geometrical isomers for [Co(en)₂(NO₂)₂]Br)

z = 2 (optically active isomers for [Co(en)₂(NO₂)₂]Br)

[yw - xz] = [(2)(5) - (3)(2)] = 10 - 6 = 4.

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