Chemistry - Coordination Chemistry Question with Solution | TestHub

$[PtC{l}_4{]}^{2-}$ (A): $P{t}^{2+}$ undergoes $ds{p}^2$ hybridization, making it square planar (S) and diamagnetic (Q).

$[NiC{l}_4{]}^{2-}$ (B): $N{i}^{2+}$ with weak field $C{l}^{-}$ ligands is $s{p}^3$ hybridized (tetrahedral), making it isostructural with $NaB{F}_4$ (R) and paramagnetic (P) due to unpaired electrons.

$[Fe{F}_6{]}^{3-}$ (C): $F{e}^{3+}$ is an outer orbital octahedral complex ($s{p}^3{d}^2$), making it paramagnetic (P) and isostructural with the octahedral anion in $Cs[PC{l}_6]$ (T).

$[ZnC{l}_4{]}^{2-}$ (D): $Z{n}^{2+}$ is $d^{10}$, resulting in a tetrahedral $s{p}^3$ geometry (isostructural with $NaB{F}_4$, R) and a diamagnetic nature (Q).