Chemistry - Coordination Chemistry Question with Solution | TestHub

(i)$\mathrm{ }{\mathrm{V}}^{+2}\left(23\right)⟹\left[\mathrm{A}\mathrm{r}\right]3{\mathrm{d}}^{3}4{\mathrm{d}}^0⟹\mathrm{ }$$\left(\mathrm{n}=3\right)$$\Rightarrow \mathrm{\mu }\sqrt{3\left(3+2\right)}=3.87$
(ii)$\mathrm{C}{\mathrm{r}}^{+2}\left(24\right)⟹\left[\mathrm{A}\mathrm{r}\right]3{\mathrm{d}}^4$$\left(\mathrm{n}=2\right)$$\Rightarrow \mathrm{\mu }\sqrt{2\left(2+2\right)}=2.82$
(iii)$\mathrm{ }\mathrm{ }\mathrm{R}{\mathrm{u}}^{+3}\left(44\right)⟹\left[\mathrm{k}\mathrm{r}\right]4{\mathrm{d}}^5$$\mathrm{ }(\mathrm{n}=1)$$\Rightarrow \mathrm{\mu }\sqrt{1\left(1+2\right)}=3$
(iv)$\mathrm{ }\mathrm{ }\mathrm{F}{\mathrm{e}}^{+2}\left(26\right)\mathrm{ }⟹\left[\mathrm{A}\mathrm{r}\right]3{\mathrm{d}}^6\mathrm{ }$$(\mathrm{n}=0)$$\Rightarrow \mathrm{\mu }=0$
Order of magnetic moment will be$\propto$no. of unpaired${\mathrm{e}}^{-}$
${\mathrm{V}}^{+2}>\mathrm{ }\mathrm{C}{\mathrm{r}}^{+2}>\mathrm{R}{\mathrm{u}}^{+3}\mathrm{ }>\mathrm{F}{\mathrm{e}}^{+2}$
$\mathrm{\mu }=\sqrt{\mathrm{n}(\mathrm{n}+2)}$B.M. Hence more the value of$\mathrm{n}$more will be magnitude moment.