Chemistry - Coordination Chemistry Question with Solution | TestHub

Linkage Isomers: Both $N{O}_2^{-}$ ($-N{O}_2$, $-ONO$) and $SC{N}^{-}$ ($-SCN$, $-NCS$) are ambidentate ligands, creating $2\times 2=4$ linkage combinations.

Stereoisomers per Linkage: Each combination forms a $[M(A)(B)(en{)}_2]$ complex, yielding a trans-isomer (optically inactive) and a cis-isomer (optically active, existing as a $d/l$ enantiomeric pair).

Total Isomers ($Y$): With 3 stereoisomers per linkage form, the total number of isomers is $Y=4\times 3=12$.

Final Value: Calculating the required ratio gives $\frac{Y}{2}=\frac{12}{2}=6$.