Chemistry - Coordination Chemistry Question with Solution | TestHub

Both complexes, $[\mathrm{Cr}({\mathrm{H}}_2\mathrm{O}{)}_6{]}^{3+}$ and $[\mathrm{Co}({\mathrm{H}}_2\mathrm{O}{)}_6{]}^{3+}$, are octahedral and involve ${\mathrm{sp}}^3{\mathrm{d}}^2$ hybridization (outer orbital complex) or ${\mathrm{d}}^2{\mathrm{sp}}^3$ hybridization (inner orbital complex). Since water is a weak field ligand, both are high spin, ${\mathrm{d}}^2{\mathrm{sp}}^3$ hybridized. Therefore, they do not differ in hybridization.