For the complex compound [ Fe ( H 2 O ) 5 NO ] SO 4 , true statements are :

Question

For the complex compound [ Fe ( H 2 ​ O ) 5 ​ NO ] SO 4 ​ , true statements are :

TestHub · Accepted Answer

Oxidation State: In the brown ring complex $[F e (H_{2} O)_{5} NO] S O_{4}$ , NO exists as $N O^{+}$ , meaning iron is in the $+ 1$ oxidation state with a $3 d^{7}$ configuration.

Statement A (True): $E A N = Z - O x i d a t i o n St a t e + 2 (C oor d ina t i o n N u mb er) = 26 - 1 + 2 (6) = 37$ .

Statement C (True) & B (False): As H₂O is a weak-field ligand, $3 d^{7}$ forms a high-spin complex with configuration $(t_{2 g})^{5} (e_{g})^{2}$ containing 3 unpaired electrons, giving a magnetic moment of $3 (3 + 2) = 15 BM$ .

Statement D (True): The bond order of isolated NO is $2.5$ , whereas in the complex it exists as $N O^{+}$ with a higher bond order of $3$ , making the N–O bond stronger.

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