Chemistry - Coordination Chemistry Question with Solution | TestHub

 

 

A. $[Pt(N{H}_3{)}_4][PtC{l}_4]$: This complex has Pt, NH₃, and Cl ligands. A possible non-electrolyte polymerization isomer would be $[Pt(N{H}_3{)}_{2}C{l}_2]$, which is a known neutral complex. This option CAN form a non-electrolyte polymerization isomer.

 

B. $[Fe(N{H}_3{)}_6][Fe(CN{)}_6]$: This complex has Fe, NH₃, and CN ligands. A possible non-electrolyte polymerization isomer would be $[Fe(N{H}_3{)}_3(CN{)}_3]$, which is a neutral complex. This option CAN form a non-electrolyte polymerization isomer.

 

C. $[Co(en{)}_3][Co(N{O}_2{)}_6]$: This complex contains ethylenediamine (en) ligands. The empirical formula would involve Co, en, and NO₂.

The complexes possible with en and NO₂ are $\left[Co{\left(en\right)}_2{\left(N{O}_2\right)}_2\right]$ or $\left[Co\left(en\right){\left(N{O}_2\right)}_4\right]$ which does not match the empirical formula.

 

 

D. $[Co(N{H}_3{)}_{5}N{O}_2{]}_3[Co(N{O}_2{)}_6{]}_2$: This complex has Co, NH₃, and NO₂ ligands. The overall ratio of Co:NH₃:NO₂ is $(3\times 1+2\times 1):(3\times 5):(3\times 1+2\times 6)=5:15:15$, which simplifies to $1:3:3$. This matches the empirical formula $Co(N{H}_3{)}_3(N{O}_2{)}_3$

 

. Therefore, this complex CAN form a non-electrolyte polymerization isomer.

 

Final Answer: The final answer is C.