Chemistry - Salt Analysis Question with Solution | TestHub

Both react with NaOH

${\mathrm{Cu}}^{2+}$ gives blue ppt of $\mathrm{Cu}(\mathrm{OH}{)}_2$ whereas, ${\mathrm{Fe}}^{2+}$ gives $\mathrm{Fe}(\mathrm{OH}{)}_2$ [green ppt] with NaOH

${\mathrm{Cu}}^{2+}$ gives chocolate brown ppt whereas ${\mathrm{Fe}}^{2+}$ gives dark blue ppt with $K_4\left[Fe(CN{)}_6\right]$

Both have four unpaired electrons