Chemistry - Coordination Chemistry Question with Solution | TestHub

(a) Zn²⁺ (Z = 30) $1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}3{\mathrm{s}}^{2}3{\mathrm{p}}^{6}3{\mathrm{d}}^{10}$.

Cu⁺ (Z = 29) $1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}3{\mathrm{s}}^{2}3{\mathrm{p}}^{6}3{\mathrm{d}}^{10}$.

Both species are diamagnetic.

(b) Co²⁺ (Z = 27) $1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}3{\mathrm{s}}^{2}3{\mathrm{p}}^{6}3{\mathrm{d}}^7$ (3 unpaired electrons).

Ni²⁺ (Z = 28) $1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}3{\mathrm{s}}^{2}3{\mathrm{p}}^{6}3{\mathrm{d}}^8$ (2 unpaired electrons).

(c) Mn⁴⁺ (Z = 25) $1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}3{\mathrm{s}}^{2}3{\mathrm{p}}^{6}3{\mathrm{d}}^3$ (3 unpaired electrons).

Co²⁺ (Z = 27) $1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}3{\mathrm{s}}^{2}3{\mathrm{p}}^{6}3{\mathrm{d}}^7$ (3 unpaired electrons).

Both species are paramagnetic, and their magnetic moments are the same.

(d) Mg²⁺ (Z = 12) $1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^6$ (no unpaired electrons).

Sc⁺ (Z = 21) $1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}3{\mathrm{s}}^{2}3{\mathrm{p}}^{6}3{\mathrm{d}}^{1}4{\mathrm{s}}^1$ (2 unpaired electrons).