Chemistry - Coordination Chemistry Question with Solution | TestHub

An outer orbital complex uses outer d-orbitals (e.g., 4d for 3d metals) for hybridization. This typically occurs with weak field ligands, leading to high spin complexes.

For $[Ni(N{H}_3{)}_6{]}^{2+}$, Ni is in the +2 oxidation state ($d^8$). NH₃ is a weak field ligand for Ni²⁺, resulting in a high spin complex with $s{p}^3{d}^2$ hybridization, making it an outer orbital complex.