Consider different complexes form in given reaction sequence and find ( X + Y ) . • X = Molecular weight of complex which forms in the step when oxidation number of cobalt is changed • Y = Molecular w

Question

Consider different complexes form in given reaction sequence and find $(X + Y)$ .

• X = Molecular weight of complex which forms in the step when oxidation number of cobalt is changed • Y = Molecular weight of complex whose ionisation isomer is also present in given reaction sequence [Atomic weight. of Co = 59, Br = 80, S = 32, O = 16] [Molecular weight of NH₃ = 17, H₂O = 18]

TestHub · Accepted Answer

Oxidation State Change (Finding X): Cobalt is oxidized from $+ 2$ to $+ 3$ during the first step, forming the complex $[C o (N H_{3})_{5} (H_{2} O)] B r_{3}$ .

Calculation of X: $X = 59 + (5 \times 17) + 18 + (3 \times 80) = 402$ .

Ionization Isomers (Finding Y): The sequence contains the ionization isomers $[C o (N H_{3})_{5} B r] S O_{4}$ and $[C o (N H_{3})_{5} (S O_{4})] B r$ .

Calculation of Y: $Y = 59 + (5 \times 17) + 80 + 32 + (4 \times 16) = 320$ .

Final Answer: Therefore, $X + Y = 402 + 320 = 722$ .

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