Number of geometrical isomer( s ) of square planar complex [ RhCl ( PPh 3 ) ( H 2 O ) ( CO ) ] is-

Question

Number of geometrical isomer( s ) of square planar complex [ RhCl ( PPh 3 ​ ) ( H 2 ​ O ) ( CO ) ] is-

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Explain the question:

Find number of geometrical isomers of square planar complex $[RhCl (PPh_{3}) (H_{2} O) (CO)]$ .

Concept:

This question is based on geometrical isomerism in square planar $[M, A, B, C, D]$ -type complexes.

Solution:

In square planar complexes with four different ligands ( $[M, A, B, C, D]$ type), geometrical isomerism arises due to different possible cis/trans pairings.

The number of geometrical isomers for four different ligands is 3. These are based on how ligands are placed adjacent (cis) or opposite (trans) to each other.

So, for $[RhCl (PPh_{3}) (H_{2} O) (CO)]$ , possible unique geometrical arrangements = 3.

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