Given below are two statements :
Statement I: ${[Mn (CN)_{6}]}^{3 -}, {[Fe (CN)_{6}]}^{3 -}$ and ${[Co {(C_{2} O_{4})}_{3}]}^{3 -}$ are $d^{2} {sp}^{3}$ hybridised.
Statement II : ${[{MnCl}_{6}]}^{3 -}$ and ${[{FeF}_{6}]}^{3 -}$ are paramagnetic and have $4$ and $5$ unpaired electrons, respectively.

Question

Given below are two statements :
Statement I:

{[Mn (CN)_{6}]}^{3 -}, {[Fe (CN)_{6}]}^{3 -}

and

{[Co {(C_{2} O_{4})}_{3}]}^{3 -}

are

d^{2} {sp}^{3}

hybridised.
Statement II :

{[{MnCl}_{6}]}^{3 -}

and

{[{FeF}_{6}]}^{3 -}

are paramagnetic and have

4

and

5

unpaired electrons, respectively.

TestHub · Accepted Answer

CN - is strong field ligand. C 2 O 4 2 - is chelating ligand. Mn 3 + has d 4 configuration. Fe 3 + has d 5 configuration. Co 3 + has d 6 configuration. ⇒ All will have larger splitting values hence, they undergo d 2 sp 3 hybridisation. MnCl 6 3 - FeF 6 3 - d 4 configuration, Cl - d 5 configuration, F -

Chemistry - Coordination Chemistry Question with Solution | TestHub

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