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ChemistryCoordination ChemistryMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

The spin only magnetic moment of transition metal ion found to be $5 .92 BM$ . The number of unpaired electrons present in the species is:

Answer:

5.00

Solution:

Spin only magnetic moment, $μ = \sqrt{n(n+2)} BM$
where $n$ = no. of unpaired electrons there; $\sqrt{n(n + 2)} = 5 .92$
$∴ n = 5$

Stream:NTA_ABHYASSubject:ChemistryTopic:Coordination ChemistrySubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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