Arrange the following coordination compounds in the increasing order of magnetic moments. (Atomic numbers: $Mn = 25; Fe = 26$ )
A. ${[{FeF}_{6}]}^{3 -}$
B. ${[Fe {(CN)}_{6}]}^{3 -}$
C. ${[{MnCl}_{6}]}^{3 -}$ (high spin)
D. ${[Mn {(CN)}_{6}]}^{3 -}$
Choose the correct answer from the options given below

Question

Arrange the following coordination compounds in the increasing order of magnetic moments. (Atomic numbers: $Mn = 25; Fe = 26$ )

A. ${[{FeF}_{6}]}^{3 -}$

B. ${[Fe {(CN)}_{6}]}^{3 -}$

C. ${[{MnCl}_{6}]}^{3 -}$ (high spin)

D. ${[Mn {(CN)}_{6}]}^{3 -}$

Choose the correct answer from the options given below

TestHub · Accepted Answer

Magnetic moment is directly proportional to the number of unpaired in the central metal atom of a complex.

It is calculated by the formula, $μ = \sqrt{n (n + 2)} BM$

(A) ${[{FeF}_{6}]}^{3 -}$

${Fe}^{+ 3} \to 3 d^{5} 4 s^{0}$

$n = 5$

(B) ${[Fe {(CN)}_{6}]}^{3 -}$

${Fe}^{+ 3} \to 3 d^{5} 4 s^{0}$

$n = 1$

(C) ${[{MnCl}_{6}]}^{3 -}$

${Mn}^{+ 3} \to 3 d^{4} 4 s^{0}$

$n = 4$

(D) ${[Mn {(CN)}_{6}]}^{3 -}$

${Mn}^{+ 3} \to 3 d^{4} 4 s^{0}$

$n = 2$

$Hence, correct order of magnetic moment is A > C > D > B$

Chemistry - Coordination Chemistry Question with Solution | TestHub