An element "X" which belongs to VIII th group of Mendeleev's table has exactly 20 electrons having ℓ = 2 . The element forms complex of the type XCl 2 .2 NH 3 . Then, the correct statement(s)

Question

An element "X" which belongs to VIII th group of Mendeleev's table has exactly 20 electrons having ℓ = 2 . The element forms complex of the type XCl 2 ​ .2 NH 3 ​ . Then, the correct statement(s) is/are.

TestHub · Accepted Answer

Element X is Palladium (Pd), which belongs to Group VIII and has 20 d-electrons ( $3 d^{10} 4 d^{10}$ ).

Statement A is correct: $[P d (N H_{3})_{2} (Cl)_{4}]$ is a non-electrolyte ( $i = 1$ ), whereas $[P d (N H_{3})_{4} C l_{2}] C l_{2}$ dissociates into 3 ions ( $i = 3$ ), resulting in a smaller freezing point depression for the former.

Statement B is correct: $P d^{2 +}$ has a $d^{8}$ configuration ( $[Kr] 4 d^{8}$ ) with two unpaired electrons as a free ion, making it paramagnetic.

Statement C is correct: The complex $P d C l_{2} B r_{2} \cdot 4 N H_{3}$ forms exactly 4 distinct ionization isomers by varying the counter-ions in the outer sphere: $[P d (N H_{3})_{4} C l_{2}] B r_{2}$ , $[P d (N H_{3})_{4} B r_{2}] C l_{2}$ , and two stereoisomeric forms of $[P d (N H_{3})_{4} (Cl) (B r)] ClB r$ .

Chemistry - Coordination Chemistry Question with Solution | TestHub

Options:(select one or more)

Doubts & Discussion