The overall stability constant of the complex ion Cu NH 3 4 2 + is 2 . 1 × 10 13 . The overall dissociation constant is y × 10 - 14 . Then y is (Nearest integer)

Dissociation constant = 1 stability constant = 1 2 . 1 × 10 13 = 100 × 10 - 14 21 = 4 . 7 × 10 - 14 ≈ 5 × 10 - 14

Chemistry - Coordination Chemistry Question with Solution | TestHub

ChemistryCoordination ChemistryIntroduction, About ligandMedium2 minPYQ_2021

ChemistryMediumnumerical

The overall stability constant of the complex ion ${[Cu {({NH}_{3})}_{4}]}^{2 +}$ is $2.1 \times 10^{13} .$ The overall dissociation constant is $y \times 10^{- 14}$ . Then $y$ is (Nearest integer)

Answer:

5.00

Solution:

Dissociation constant $= \frac{1}{stability constant} = \frac{1}{2.1 \times 10^{13}} = \frac{100 \times 10^{- 14}}{21}$

$= 4.7 \times 10^{- 14}$

$\approx 5 \times 10^{- 14}$

Stream:JEESubject:ChemistryTopic:Coordination ChemistrySubtopic:Introduction, About ligand

⏱ 2mℹ️ Source: PYQ_2021

Doubts & Discussion

Loading discussions...