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ChemistryCoordination ChemistryVBT,CFT(complex compound)Easy2 minPYQ_2020

ChemistryEasynumerical

Considering that $Δ_{0} > P$ , the magnetic moment (in BM) of ${[Ru {(H_{2} O)}_{6}]}^{2 +}$ would be

Answer:

0.00

Solution:

${Ru}^{2 *} = 4 d^{6} = t 2 g^{2, 2.2} {eg}^{0, 0}$ since $Δ_{0} > P$
No. of unpaired electrons = zero
Magnetic Moment $= 0$

Stream:JEESubject:ChemistryTopic:Coordination ChemistrySubtopic:VBT,CFT(complex compound)

⏱ 2mℹ️ Source: PYQ_2020

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