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ChemistryCoordination ChemistryMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

The EAN of $Zn$ in ${[Zn {({NH}_{3})}_{4}]}^{2 +}$ is

Answer:

36.00

Solution:

$Z =$ atomic number of $(Zn)$ metal $= 30$
$X =$ number of electrons lost during oxidation of metal to metal ion $= 2$
$Y =$ number of electrons donated by ligands $= (4 \times 2) = 8$
$EAN = Z - X + Y = 30 - 2 + 8 = 36$

Stream:NTA_ABHYASSubject:ChemistryTopic:Coordination ChemistrySubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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