What will be the normality of a solution obtained by mixing 0.45 N and 0.60 N NaOH solutions in the ratio 2 : 1 by volume ?

Question

TestHub · Accepted Answer

To find the normality of the mixture, use the formula $N_{mi x} V_{mi x} = N_{1} V_{1} + N_{2} V_{2}$ .

Given $N_{1} = 0.45$ N, $N_{2} = 0.60$ N, and $V_{1} : V_{2} = 2 : 1$ . Let $V_{1} = 2 V$ and $V_{2} = V$ .

Then $V_{mi x} = V_{1} + V_{2} = 2 V + V = 3 V$ .

$N_{mi x} (3 V) = (0.45) (2 V) + (0.60) (V)$

$N_{mi x} (3 V) = 0.90 V + 0.60 V$

$N_{mi x} (3 V) = 1.50 V$

$N_{mi x} = \frac{1.50 V}{3 V} = 0.50$ N.

The normality of the resulting solution is 0.50 N.

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