To a 10 ml H 2 O 2 solution, excess of acidified solution of potassium iodide was added. The iodine liberated required 25 ml of 0.2 N N a 2 S 2 O 3 solution. The volume strength of the H 2

Question

To a 10 ml H 2 ​ O 2 ​ solution, excess of acidified solution of potassium iodide was added. The iodine liberated required 25 ml of 0.2 N N a 2 ​ S 2 ​ O 3 ​ solution. The volume strength of the H 2 ​ O 2 ​ solution is

TestHub · Accepted Answer

The milliequivalents (meq) of I₂ are calculated as $25 \times 0.2 = 5$ meq. This value is equal to the meq of H₂O₂ in 10 mL.

Therefore, the normality ( $N$ ) of H₂O₂ is $5/10 = 0.5 N$ .

The volume strength is calculated as $5.6 \times 0.5 = 2.8$ . This corresponds to option (c).

Chemistry - Redox Reactions Question with Solution | TestHub

Options:

Doubts & Discussion

JEE Advanced 2028 (Class 11)