Chemistry - Concentration Terms Question with Solution | TestHub

ChemistryConcentration TermsMiscellaneous/MixedMedium2 minQB

ChemistryMediumnumerical

Passage / Comprehension

A sample of urine containing 0.3 g urea was treated with excess 0.2 M nitrous acid. $NH_{2} CONH_{2} + 2 HNO_{2} \to CO_{2} + 2 N_{2} + 3 H_{2} O$ The gases produced are passed through aq. KOH and final volume is measured. ( $R = 0.082 L -$ atm $/ K - mol$ )

Volume of $HNO_{2}$ consumed by urea is $____$ (in mL)

Answer:

50.00

Solution:

Final mmol of gas mixture (N₂) = 10

$V = \frac{10 \times 1 0 ^{- 3} \times 0.0821 \times 298}{1} = 244.65 m L$

$mm o l o f H N O_{2} = 10 = 0.2 \times V_{(m L)}$

$V = 50 m L$

Stream:JEESubject:ChemistryTopic:Concentration TermsSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: QB

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