Chemistry - Concentration Terms Question with Solution | TestHub

ChemistryConcentration TermsConcentration termMedium2 minQB

ChemistryMediuminteger

When 20 ml of pure acetic acid (density $= 0.75 gm ml^{- 1}$ ) is mixed with 50 gm of water ( density $= 1 gm ml^{- 1}$ ) at a certain temperature. Calculate the molality of acetic acid in the final solution.

Answer:

Solution:

Mass of acetic and $= 0.75 \times 20 = 15 g$

Mass of water $= 50 g$

$m = \frac{15 \times 1000}{60 \times 50} = 5 molal$

Stream:JEESubject:ChemistryTopic:Concentration TermsSubtopic:Concentration term

⏱ 2mℹ️ Source: QB

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