Chemistry - Concentration Terms Question with Solution | TestHub

ChemistryConcentration TermsConcentration termMedium2 minPYQ_2024

ChemistryMediumassertion reason

The density of ' $x$ ' $M$ solution (' $X$ ' molar) of $NaOH$ is $1.12 g mL^{- 1}$ , while in molality, the concentration of the solution is $3 m (3 molal)$ . Then $x$ is (Given : Molar mass of $NaOH$ is $40 g / mol$ )

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Answer:

Solution:

$Molality = \frac{1000 \times M}{1000 \times d - M \times ( Mw ) _{solute}} 3 = \frac{1000 \times x}{1000 \times 1.12 - ( x \times 40 )} x = 3$

Stream:JEESubject:ChemistryTopic:Concentration TermsSubtopic:Concentration term

⏱ 2mℹ️ Source: PYQ_2024

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