Chemistry - Concentration Terms Question with Solution | TestHub

ChemistryConcentration TermsConcentration termHard2 minPYQ_2024
ChemistryHardassertion reason

Volume of3M NaOH(formula weight40 g mol-1) which can be prepared from84 gofNaOHis ____×10-1dm3.

Answer:
7
Solution:

Number of moles = Mass / Molar mass​

Molar mass of NaOH=40 g/mol

By Using  the definition of molarity to find the volume of the solution:

Molarity= Number of moles of soluteVolume of solution (in liters)

M=nNaOHVsol( in L)3=(84/40)VV=0.7 L=7×10-1 L

Stream:JEESubject:ChemistryTopic:Concentration TermsSubtopic:Concentration term
2mℹ️ Source: PYQ_2024

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