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Chemistry - Concentration Terms Question with Solution | TestHub

ChemistryConcentration TermsConcentration termEasy2 minPYQ_2020

ChemistryEasysingle choice

What volume of 75% alcohol by mass $(d = 0.8 g / c m^{3})$ must be used to prepare 150 cc of 30% alcohol by mass $(d = 0.9 g / c m^{3})$ ?

Options:

Answer:

Solution:

$M_{1} V_{1} = M_{2} V_{2}$
$ρ = \frac{W_{r}}{V_{4}}$
$V_{r} = \frac{W_{r}}{ρ}$
$\frac{75}{100} \times V \times 0.8 = \frac{30}{100} \times 150 \times 0.9$
$V = 67.5$ ml

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Concentration TermsSubtopic:Concentration term

⏱ 2mℹ️ Source: PYQ_2020

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