4 g of NaOH present in 0.1 d m 3 solution has specific gravity 1.038 g mL . The normality of N a O H solution is?

Volume of solution = 0.1 L i t r e Normality of N a O H s o l u t i o n = E q u i v a l e n t o f N a O H V o l u m e i n l i t r e N = 4 40 0.1 = 1 N

Start Free Mock LoginAlready registered? Login here

Chemistry - Concentration Terms Question with Solution | TestHub

ChemistryConcentration TermsConcentration termEasy2 minPYQ_2020

ChemistryEasysingle choice

$4 g$ of $NaOH$ present in $0.1 d m^{3}$ solution has specific gravity $1.038 \frac{g}{mL}$ . The normality of $N a O H$ solution is?

Options:

Answer:

Solution:

Volume of solution $= 0.1 L i t r e$

Normality of $N a O H s o l u t i o n = \frac{E q u i v a l e n t o f N a O H}{V o l u m e i n l i t r e}$

$N = \frac{\frac{4}{40}}{0.1} = 1 N$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Concentration TermsSubtopic:Concentration term

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...