Chemistry - Concentration Terms Question with Solution | TestHub

Given

${\text{CaCO}}_{\text{3}}\text{(s)}\text{+}\text{2HCl(aq)}\to {\text{CaCl}}_{\text{2}}\text{(aq)}\text{+}{\text{CO}}_{\text{2}}\text{(g)}\text{+}{\text{H}}_{\text{2}}\text{O(l)}$

Moles present in$\text{25}\text{ml}$of$0.75\text{M}\text{HCl}=\frac{0.75}{1000}\times 25$

$=0.01875$moles

Since 2 moles react completely with${\text{CaCO}}_{\text{3}}\text{=}\text{100}\text{g}$

$\text{0}\text{.01875}$moles react completely with${\text{CaCO}}_{\text{3}}\text{=}\frac{\text{100}}{\text{2}}\text{×}\text{0}\text{.01875}$

$=0.9375\text{g}$