Chemistry - Concentration Terms Question with Solution | TestHub

ChemistryConcentration TermsConcentration termEasy2 minPYQ_2020

ChemistryEasysingle choice

Molarity, normality and molality of the solution containing $22 %$ of $A l_{2} (S O_{4})_{3} {d = 1.253 g / m L}$ by weight are

Options:

Answer:

Solution:

Molarity $= \frac{% \times 10 \times d}{G M M} = \frac{22 \times 10 \times 1.253}{342} = 0.805$ $M$
Normality $= \frac{% \times 10 \times d}{G E M}$ $= \frac{22 \times 10 \times 1.253}{342 / 6} = 4.83$ $N$
Molality $= \frac{22 \times 1000}{342 (100 - 22)} = 0.825$ $m$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Concentration TermsSubtopic:Concentration term

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...