The average molar mass of chlorine is 35 . 5 g mol - 1 . The ratio of Cl 35 to Cl 37 in naturally occurring chlorine is close to :

35 CI 37 CI Molar ratio x 1 − x M avg . = 35 × x + 37 1 − x = 35 .5 35 x + 37 − 37 x = 35 .5 2 x = 1 .5 x = 3 4 So, ratio of 35 CI : 37 CI = 3 : 1

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ChemistryConcentration TermsConcentration termEasy2 minPYQ_2020

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The average molar mass of chlorine is $35.5 g {mol}^{- 1}$ . The ratio of ${}^{35}{Cl}$ to ${}^{37}{Cl}$ in naturally occurring chlorine is close to :

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Solution:

$\begin{matrix} ^{35} CI & ^{37} CI \\ Molar ratio & x & 1 - x \end{matrix}$

$M_{avg} . = 35 \times x + 37 (1 - x) = 35 .5$

$35 x + 37 - 37 x = 35 .5$

$2 x = 1 .5$

$x = \frac{3}{4}$

So, ratio of $^{35} CI :^{37} CI = 3 : 1$

Stream:JEESubject:ChemistryTopic:Concentration TermsSubtopic:Concentration term

⏱ 2mℹ️ Source: PYQ_2020

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