Chemistry - Concentration Terms Question with Solution | TestHub

Weight of ${\mathrm{H}}_2{\mathrm{SO}}_4=10\mathrm{g}$ Weight of solution $=100\mathrm{g}$ $\begin{array}{rl}\text{ Volume of solution }& =\frac{\text{ Mass of solution }}{\text{ Density of solution }}\\ & =\frac{100}{1.1}=90.91\mathrm{mL}\end{array}$ $\begin{array}{rl}& \text{ Normality }=\frac{n_{{\mathrm{H}}_2{\mathrm{SO}}_4}\times 1000}{\text{ Volume of solution (in mL) }}\\ & =\frac{w_{{\mathrm{H}}_2{\mathrm{SO}}_4}\times 1000}{{\mathrm{GEM}}_{{\mathrm{H}}_2{\mathrm{SO}}_4}\times \text{ Volume of solution (in mL) }}\end{array}$ $=\frac{10\times 1000}{\left(\frac{98}{2}\right)\times 90.91}=2.24\mathrm{N}$