For C 70 molecule If X = Number of pentagons Y = Number of Hexagons Z = Number of C-C linkages P = Total number of orbital used in the hybridisation of one C-atom then calculate. Z – (X+Y+P)

Question

For C 70 ​ molecule If X = Number of pentagons Y = Number of Hexagons Z = Number of C-C linkages P = Total number of orbital used in the hybridisation of one C-atom then calculate. Z – (X+Y+P)

TestHub · Accepted Answer

For C₇₀ molecule:

X = Number of pentagons = 12

Y = Number of hexagons = 25

Z = Number of C-C linkages = 105

P = Total number of orbitals used in the hybridization of one C-atom = 3 (sp² hybridization)

Calculation:

Z - (X + Y + P) = 105 - (12 + 25 + 3) = 105 - 40 = 65

The final answer is 65.

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