Calculate the value of (P × Q), where
P = number of pseudo-halide ions among : (CN⁻, N₃⁻, OCN⁻, SCN⁻, SeCN⁻)
Q = number of existing oxyacids among : (HClO₂, HBrO₃, HIO₃, HIO₂, HClO)

Question

Calculate the value of (P × Q), where

P = number of pseudo-halide ions among : (CN⁻, N₃⁻, OCN⁻, SCN⁻, SeCN⁻)

Q = number of existing oxyacids among : (HClO₂, HBrO₃, HIO₃, HIO₂, HClO)

TestHub · Accepted Answer

All five ions (CN⁻, N₃⁻, OCN⁻, SCN⁻, SeCN⁻) are pseudo-halide ions → P = 5. Existing oxyacids : HClO₂ (chlorous), HBrO₃ (bromic), HIO₃ (iodic), HClO (hypochlorous) → Q = 4 ; HIO₂ (iodous acid) does not exist. P × Q = 5 × 4 = 20.

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