In an Ostwald process: N H 3 + O 2 Δ Pt x + H 2 O NO + O 2 y y + H 2 O ( e x cess ) x + z The incorrect option is:

Question

In an Ostwald process: N H 3 ​ + O 2 ​ Δ Pt ​ x + H 2 ​ O NO + O 2 ​ ​ y y + H 2 ​ O ( e x cess ) ​ x + z The incorrect option is:

TestHub · Accepted Answer

Question Explanation:

Based on the nature and properties of the intermediates $X, Y$ and Z , the incorrect statement is to be identified.

Concept: Manufacturing of Nitric acid

Solution:

$N H_{3} + O_{2} Δ Pt NO + H_{2} O$

$NO + O_{2} \to N O_{2}$

$N O_{2} + H_{2} O (e x cess) \to H N O_{3} + NO$

X: NO

Y: NO₂

Z: HNO₃

X: It is an odd electron species and paramagnetic in nature. It is a neutral oxide.

Y: Acidic oxide.

Z: Oxidizing agent, acid.

Final Answer: Option (A)

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