Observe the following reaction :- B 2 H 6 + 2X ⟶ 2(X → BX 3 ) Find the total number of 'X' in given following species. NH 3 , CH 3 NH 2 , (CH 3 ) 2 NH, H − , CO, PF 3 , pyridine

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TestHub · Accepted Answer

Lewis bases with a strong sigma-donor N lone pair split B₂H₆ unsymmetrically to give X→BH₃.

Counted: NH₃, CH₃NH₂, (CH₃)₂NH, pyridine.

H⁻ gives ionic BH₄⁻; CO and PF₃ are weak sigma donors (pi acceptors).

Total = 4.00 (as per printed key).

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