Given below are the statements about diborane
(a) Diborane is prepared by the oxidation of ${NaBH}_{4}$ with $I_{2}$
(b) Each boron atom is in ${sp}^{2}$ hybridized state
(c) Diborane has one bridged $3$ centre- $2$ -electron bond
(d) Diborane is a planar molecule

Question

The option with correct statement(s) is

TestHub · Accepted Answer

Diborane is prepared by the reaction of NaBH 4 with I 2 . 2 NaBH 4 + I 2 → B 2 H 6 + 2 NaI + H 2 In diborane, B is sp 3 hybridized. It is non-planar molecule and it has two 3 c - 2 e - bonds.

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