Consider the following interaction :
XeF₂ + SbF₅ → P (ionic compound)
Find the value of (X − Y)/Z, where
X = value of the F-Xe-F bond angle in XeF₂
Y = value of the adjacent F-Sb-F bond angle in the anionic part of compound P
Z = maximum number of atoms that can lie in one plane in the anionic part of P

Question

Consider the following interaction :

XeF₂ + SbF₅ → P (ionic compound)

Find the value of (X − Y)/Z, where

X = value of the F-Xe-F bond angle in XeF₂

Y = value of the adjacent F-Sb-F bond angle in the anionic part of compound P

Z = maximum number of atoms that can lie in one plane in the anionic part of P

TestHub · Accepted Answer

P = [XeF]⁺[SbF₆]⁻. XeF₂ is linear: X = 180°. [SbF₆]⁻ is octahedral: adjacent angle Y = 90°, and at most 5 atoms (Sb + 4 equatorial F) lie in one plane, Z = 5. (180 − 90)/5 = 18.

Chemistry - Complete Pblock- Question with Solution | TestHub

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