Chemistry - Complete Pblock- Question with Solution | TestHub

Diborane (B₂H₆) reacts with ammonia (NH₃) at room temperature through unsymmetrical cleavage. The reaction forms an ionic complex: $3B_2{H}_6+6N{H}_3\to 3[B{H}_2(N{H}_3{)}_2{]}^{+}[B{H}_4{]}^{-}$. Therefore, the 3 mole ionic product (A) is $[B{H}_2(N{H}_3{)}_2{]}^{+}[B{H}_4{]}^{-}$. The cationic part of this product is $[B{H}_2(N{H}_3{)}_2{]}^{+}$. Counting the coordination inside the cation, the total number of ammonia molecules present is 2.