XeF₆ undergoes stepwise hydrolysis : XeF₆ + H₂O → A ; A + H₂O → B ; B + H₂O → D.
Sum of the number of lone pairs on Xe in A, B and D = x.
Sum of the number of sigma bonds in A, B and D = y.
Find the value of (y − x).

Question

XeF₆ undergoes stepwise hydrolysis : XeF₆ + H₂O → A ; A + H₂O → B ; B + H₂O → D.

Sum of the number of lone pairs on Xe in A, B and D = x.

Sum of the number of sigma bonds in A, B and D = y.

Find the value of (y − x).

TestHub · Accepted Answer

A = XeOF₄ (1 lone pair, 5 σ), B = XeO₂F₂ (1 lone pair, 4 σ), D = XeO₃ (1 lone pair, 3 σ). x = 1 + 1 + 1 = 3 ; y = 5 + 4 + 3 = 12 ; y − x = 9.

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